Find Node Points on a Beam: Analytical Solution

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To find the node points (zero displacement) for a clamped-pinned and clamped-spring beam, the discussion focuses on solving the differential equation governing the beam's mode shapes. The general solution involves constants A, B, C, and D, which are determined by applying boundary conditions. The challenge lies in analytically finding the zeros of the resulting non-linear equation. While Newton's method was considered, it faced issues with convergence in various cases. Ultimately, an analytic solution may only be feasible under specific conditions where A and D are zero, simplifying the problem to trigonometric terms.
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Homework Statement



Find the node points (zero displacement) for a clamped-pinned and clamped-spring beam.
I am trying to figure out how to find these points on a beam of length L (constant E*I,m) for the first 3 natural frequencies.

Homework Equations


The Attempt at a Solution



\upsilon(x,t) = \sum \phi(x)*\zeta(t)
ODE:
\phi''(x) - \omega\phi(x) = F

General solution:
\phi(x) = A*sinh(\alpha*x) + B*cos(\alpha*x) - C*sin(\alpha*x) - D*cosh*(\alpha*x)

A,B,C,D to be found using boundary conditions (in this case clamped-pinned):
\phi(0)=0
\phi'(0)=0
\phi(L)=0
\phi''(L)=0My question is: the mode shape can be found by solving for the constants, etc. But how can you analytically find the zeros for this? The solution is non-linear. Is there another method I can use to find the node points?
 
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One thought I had was to use Newton's method but I've tried this and the radius of convergence seems to be too small for many of my cases.
 
Unless A=D=0, I'm pretty sure you need to solve numerically.
An analytic solution would be possible when A=D=0, since it's just trig terms then.
 
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