Find potential energy function and show that it is proportional to displacement

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SUMMARY

The potential energy function for a spring, when the origin is at the wall and the unstretched length is L, is derived from the force function F = -kx. The correct potential energy function is U(x) = kx²/2 - kLx + C, where the term -kLx accounts for the displacement from the wall. This formulation demonstrates that the potential energy is proportional to the square of the displacement from the equilibrium position of the spring.

PREREQUISITES
  • Understanding of Hooke's Law and spring force (F = -kx)
  • Basic calculus, specifically integration techniques
  • Familiarity with potential energy concepts in physics
  • Knowledge of constants of integration in mathematical functions
NEXT STEPS
  • Study the derivation of potential energy functions in classical mechanics
  • Learn about the implications of the spring constant (k) in different spring systems
  • Explore the concept of equilibrium and displacement in spring dynamics
  • Investigate the role of constants in integration and their physical significance
USEFUL FOR

Students studying classical mechanics, physics educators, and anyone interested in understanding the mathematical modeling of spring systems and potential energy functions.

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Homework Statement


Find the potential energy function for a spring if the origin is placed at the wall and the unstretched length of the spring is L. Show that with a suitable choice of the constant, this potential function is proportional to the square of the amount that the spring is stretched or compressed.

Homework Equations


F = d(h(x))/dx (F = force function)
U(x) = -h(x) (U(x) is potential energy function)

The Attempt at a Solution



Force of the spring
F = -kx

I integrated F and made the result negative to get the potential energy function
kx2/2 + C

But the Textbook solution is:
kx2/2 - kLx + C

How do I get -kLx? Also, I'm not sure about how I should start the second part of the problem.
 
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x is the distance from the wall, so the force is -k(x-L).
 

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