Find Potential Minimum of Two Point Charges

AI Thread Summary
To find the minimum electric potential of two point charges, the potential at a point on the x-axis is expressed as V = k*q1/x + k*q2/(d-x). The necessary condition for the potential to have a minimum is that its derivative, dV/dx, equals zero. This involves differentiating the potential function with respect to x and solving for x. The discussion highlights the importance of understanding the relationship between the charges and their distances to determine the point of minimum potential. The approach emphasizes the need for careful calculation of derivatives to identify critical points.
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Homework Statement


A charge of 0.611 nC is placed at the origin. Another charge of 0.383 nC is placed at x1 = 8.1 cm on the x-axis.
At which point on the x-axis does this potential have a minimum?

Homework Equations


U=(kq1q2)/r

The Attempt at a Solution


I really have no idea how to even start this problem. I've been thinking about it for a couple hours now. Any help would be appreciated.

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
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Post the complete question.
 
I edited the post. My apologies.
 
And also once I messed up enough the hint was that
"A necessary condition for the potential to have a minimum is that its derivative is 0."

But the derivative of what? The only thing I can think of is the V(r)=kQ/r
 
Potential at a point distance x from q1 is given by

V = k*q1/x + k*q2/(d-x) where d is the distance between the charges.

To find the minimum potential between the charge, find dV/dx and equate it to zero.
And find x.
 
Thanks a lot! It was kind of a messy derivative but I am so thankful you helped me out. :)
 
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