Find Speed of Block Dropped on Spring: Mass, Height, Compression

  • Thread starter Thread starter grouchy
  • Start date Start date
  • Tags Tags
    Mass Spring
AI Thread Summary
The discussion focuses on calculating the speed of a 9.3 kg block dropped from a height of 800 cm onto a spring with a spring constant of 1086 N/m, which compresses by 50 cm. The transformation of energy is key, where gravitational potential energy (Eg) converts to kinetic energy (Ek) as the block falls, and then to elastic potential energy (Ee) upon spring compression. The user expresses confusion about applying the correct equations for energy transformation. They attempted to use the equation 1/2mv^2 = 1/2kx^2 but found it incorrect. Understanding the energy transformation process is essential for solving the problem accurately.
grouchy
Messages
72
Reaction score
0
A 9.3 kg block is dropped onto a spring of spring constant 1086 N/m from a height of 800 cm. When the block is momentarily at rest, the spring has been compressed by 50 cm. Find the speed of the block when the compression of the spring is 10 cm. The acceleration of gravity is 9.81 m/s^2. Answer in units of m/s.

Equations...
1/2kx^2
k = 1/2mv^2
u = mgh

my problem is I don't understand which equations to use in which situations,..
 
Physics news on Phys.org
This is simply a transformation of energy question.

Right at the start before the block is dropped, only gravitation potential energy (Eg) is present. Then all of the Eg is turned into kinetic energy (Ek) as the block falls. Just before the block hits the spring, all of the Eg is turned into Ek. Then the block impacts the spring and compressing it, turning Ek into Elastic potential energy (Ee).

Therefore, it would:

Eg-->Ek-->Ee

Using this transformation method, it would be very simple to solve this.
 
If I wasn't very familiar with the whole transformation of energy...how would I do this?
 
I tried 1/2mv^2 = 1/2kx^2 and it comes out wrong..
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top