Find Stable Equilibrium for Mass m=5.34Kg w/ Force F(x)

AI Thread Summary
To find the stable equilibrium position for a mass of 5.34 kg under the force F(x)=(5.0N/m^(1/2))*(x^(1/2))-(1.0N/m)*(x), the force must be set to zero, leading to potential equilibrium points at x=0 and x=133.42. The calculation initially yielded x=0 and x=25, but further analysis confirmed x=133.42 as a valid solution. For determining the frequency of oscillation around the equilibrium position, the harmonic oscillator's differential equation can be applied, with frequency derived from the second derivative of displacement. The discussion highlights the importance of correctly incorporating mass into calculations for accurate results.
jjj2364
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I have a object of mass m=5.34Kg. There is a force acting on the object F(x)=(5.0N/m[1][/2])*(x[1][/2])-(1.0N/m)*(x).
1)I need to find the position x0 where the mass is in a condition of stable equilibrium.
2)What is the frequency of oscillation around this position? How would this frequency change if the force was F(x)=(1.0N/m)(x)

Relevant equations:
F(x)=0 in order to get the position of stable equilibrium.

The attempt at a solution
I put the force F(x)=0 and I got x=0 and x=25 but I'm not sure this is the right way to do it.
For part 2 I'm a little confused, could give some hints?

thanks
jon
 
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I put the force F(x)=0 and I got x=0 and x=25 but I'm not sure this is the right way to do it.
For part 2 I'm a little confused, could give some hints?

That's the right way to do it, but I can't check your answer because I don't understand your notation. What do m[1][/2] and x[1][/2] mean?

For part 2, think about the differential equation for a harmonic oscillator:

d2s/dt2 + w2s=0

where s represents a small deviation from the equilibrium position. Try taking the second time derivative of x, then rewriting it in the form above, using Taylor series approximations if necessary. w^2 would then give you the frequency.
 
ok
sorry i was not sure about the way to write that
this is the expression for the force
F(x)=(5.0N/m^1/2)*(x^1/2)-(1.0N/m)x

m=mass
so the first term contains the sqrt of m and the sqrt of x.
I think i made a mistake in the calculation because i didi not plug in the value for the mass. I'm going to do that again and I am going to try to do part two.
thanks!
bob
 
so i got x=0 and x=133.42
 
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