Find The Angle of The Electron; Motion of Charges

AI Thread Summary
Electrons will exit the uniform electric field at an angle of -23 degrees after passing through parallel plates that are 4.9 cm long with an electric field strength of 5.0 x 10^3 N/C. The discussion highlights the need to calculate the forces acting on the electron to determine its acceleration. The user has attempted to find the angle using the equation y = [(qE) / (2m(V)^2)] * (x)^2 but has struggled to achieve the correct result, with the closest being -12 degrees. Clarification was provided regarding the orientation of the electric field, confirming that the positive plate is on top and the negative plate is on the bottom. The conversation emphasizes the importance of understanding the forces and acceleration in solving the problem accurately.
withthemotive
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At what angle will the electrons leave the uniform electric field at the end of the parallel plates? Assume the plates are 4.9 cm long and E = 5.0 x 10^3 N/C.

*The answer to this question is -23 degrees.

So far what I have tried to do is find the position of the electron on the y-axis and then take the tangent of the x&y values. My answers so far have been off. The closest I've gotten so far is -12 degrees.

This is the equation I used:

y = [(qE) / (2m(V)^2)] * (x)^2

q= -1.6x10^-19 C
m= 9.1x10^-31 kg
 
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Let's start again from the beginning.

What are the forces acting on the electron? Can you therefore determine the acceleration of the electron?

*Clarification: Does the question mention the orientation of the field/plates? Is the electric field directed vertically upwards/downwards or horizontally for example?
 
Yeah, the orientation of the plates is negative on bottom and positive on top.
 
withthemotive said:
Yeah, the orientation of the plates is negative on bottom and positive on top.
Okay, thanks.
Hootenanny said:
What are the forces acting on the electron? Can you therefore determine the acceleration of the electron?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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