Find the capacitance of C3 and its charge

AI Thread Summary
The discussion focuses on finding the capacitance and charge of capacitor C3, emphasizing the correct formula for voltage, V = Q/C. Participants clarify that this formula is essential for solving part (a) of the problem. It is noted that part (b) can be approached without needing the answer from part (a), simplifying the calculations. Additionally, there is a suggestion to improve the presentation of the homework pages using matrices and determinants. Overall, the conversation revolves around correcting misunderstandings and enhancing problem-solving strategies.
Kelsi_Jade
Messages
58
Reaction score
0

Homework Statement


From the textbook:
upload_2017-3-27_9-20-2.png


Homework Equations

/ 3. The Attempt at a Solution
My attempt at the solution: looking to fix my issues and help correcting my work.[/B]
upload_2017-3-27_9-20-24.png

upload_2017-3-27_9-21-49.png
 
Physics news on Phys.org
You have used incorrect formula for voltage across capacitor.

You need to write the voltage across capacitor in terms of charge and capacitance.
 
Should be V=Q/C?
 
Kelsi_Jade said:
Should be V=Q/C?
Yes.
 
So, would this be accurate?

upload_2017-3-27_17-19-31.png
 
I think that's right for (a). Much better than before. :approve:

For (b) you don't actually need the answer to (a). You might be able to say it off back of head. :oldwink:

After which calculation of (a) is a bit simpler.

Here Matrices and determiants is how you can make pages like yours look better.
 
Last edited:
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top