Find the change of internal energy of the air.

AI Thread Summary
To find the change in internal energy of air in a car tire, the formula U=5/2nRT is used, considering air as a mixture of diatomic gases. The number of moles (n) is calculated using the ideal gas law, resulting in approximately 3.7 moles. After determining the final temperature from the pressure change, the internal energy is calculated to be around 2500 J, which aligns closely with the textbook answer of 2537 J when accounting for significant figures. The discussion emphasizes the importance of using the correct gas constant and significant figures in calculations. Overall, the calculations confirm the expected change in internal energy based on the given conditions.
MaiteB
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Homework Statement


A car rubber has the volume 50 liters when it is bloated in a pressur 1.8 atm and in a temperature 293 K. After some hours of journey as an effect of friction the pressure will become 2atm. Find the change of internal energy of the air inside the rubber (U)

Homework Equations


U=3/2nRT

The Attempt at a Solution


I thought to sue the formula U=3/2nRT, but I don't know the n.
 
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Don't forget the ideal gas law. Also, in the formula for U, are you sure the fraction is 3/2? Nitrogen and oxygen are diatomic gases.
 
TSny said:
Don't forget the ideal gas law. Also, in the formula for U, are you sure the fraction is 3/2? Nitrogen and oxygen are diatomic gases.
Ok but how can I find the U with this compound of gases like air?
 
TSny said:
Don't forget the ideal gas law. Also, in the formula for U, are you sure the fraction is 3/2? Nitrogen and oxygen are diatomic gases.
I am writing my solution: pV=nRT=>n=(1.8*10^5*0.05)/(8.31*293)=3.7
1.8/293=2/x=>x=325.5555
U= 5/2* 3.7*8.31*(325.56-293)=2500, but in my book the answer is 2537J
 
Looks good. Some of the data in the problem is given to only 2 significant figures. So, the textbook should have rounded the answer to 2 significant figures which agrees with yours.
 
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If you use 1.01325 x 105 for atm you find a better number. Your calculation is correct.
 
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