Find the Coefficient of Kinetic Friction for a 40N Case

AI Thread Summary
To find the coefficient of kinetic friction for a 40N case being moved by a 15N force at constant velocity, the force of friction must equal the applied force. Since the case is moving at constant velocity, the frictional force is 15N. The normal force acting on the case is equal to its weight, which is 40N. Using the equation for friction, the coefficient of kinetic friction (μ) is calculated as μ = frictional force / normal force, resulting in μ = 15N / 40N = 0.375. Thus, the coefficient of kinetic friction for the case is 0.375.
Mar17
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Homework Statement



a force of 15 N {south} moves a case weighing 40 N { down} across a level surface at constant velocity. what is the coefficient of kinetic friction for the cae on the counter

Homework Equations


Force of friction = the coefficient of friction(μ) x normal force

The Attempt at a Solution



Force of friction = the coefficient of friction (μ )x normal force
55N= μ x 55
=1
 
Last edited:
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If the case is moving at constant velocity, then the force of friction must exactly equal the applied force.
 
thank you. :)
 

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