Find the elements of the direct product

thetodd
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Homework Statement



Compute the direct sum Z_12 (+) U(10)

Z_24 is the group Z under addition modulo 12
U(10) is the group Z under multiplication modulo 10

The Attempt at a Solution


I have computed direct sums of Z_n groups before:

For example: Z_2 (+) Z_3 = {(0,0),(0,1),(0,2),(1,0),(1,1),(1,2)}

From this I would think I would follow a similar process but my textbook has the example:
U(8) (+) U(10) = {(1,1),(1,3),(1,7),(1,9),(3,1),(3,3),(3,7),(3,9),(5,1),(5,3),(5,7),(5,9),(7,1),(7,3),(7,7),(7,9)}

What's going on here?
 
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Maybe what you're missing is that U(10) is actually the group of invertibles in Z_10 under multiplication. Can you write down what the elements of U(10) are?
 
ok.. so U(10) = {1,3,7,9} under multiplication mod 10
and Z_12 = {0,1,2,3,4,5,6,7,8,9,10,11} under addition mod 12
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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