1. The problem statement, all variables and given/known data A system of 57.g of liquid water at 298k is heated using an immersion heater at a contsant pressure of 1 bar. If a current of 1.50 A passes through the 10.0-ohm resistor for 150s. What is the final temperature of the water? 2. Relevant equations w=VIt C=q/deta(t) V=IR C(h20)=75.3 (J/mol*k) 3. The attempt at a solution Ok so I solve the problem correctly but I am a little confused at one step. I will work through what I did to find the answer. I found the potential using V=IR=(1.5)(10)=15 volts. Since I now know the potential I found the electrical work, w=VIt=(15)(1.5)(150)=3375 J Now where I am a little confused is to find my answer I essentially used the equation of heat capacity of water: C=q/delta(T) --->T(final)=q/(C*n)+T(initial)=312k But I didnt use heat (q) from the internal system, I used the value from electrical work (w). Thermodynamics is a fairly new topic for me so forgive me if this seems like a rediculous question. But why did I get the right answer if I used work instead of heat? Is it because delta(U)= q + w = 0 and the system did work on the suroundings (so making it negative work), thus making q=w? I'd appreciate any help on this. Thanks.