Find the final temperature of the ball

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To find the final temperature of a copper ball with a radius of 1.5 cm that has expanded due to heating, the coefficient of linear expansion for copper is utilized, which is 17 x 10^-6. The coefficient of volume expansion is determined to be three times this value. The volume change is calculated to be approximately 0.54. Initially, there was confusion regarding the application of the equation delta V = BV(delta T), but the correct approach involves adding the room temperature of 22°C to the calculated temperature change. The final temperature of the ball is confirmed to be 410.27°C.
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A copper ball with a radius of 1.5 cm is heated until its diameter has increased by 0.20 mm. Assuming a room temperature of 22°C, find the final temperature of the ball.
 
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What have you tried?
 
well, I know that the coefficient of linear expansion for copper is 17 x 10^-6, so it's coefficient of volume expansion is 3 times that.. and I know that the volume has changed by about .54. I'm not really sure what to do with this though
 
I assume I'm using the equation delta V = BV(delta T), but when I do this I get a huge number
 
nevermind, I got it. I was subtracting 22 instead of adding it. The answer is 410.27 right?
 

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