Find the height of each right cylinder

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To determine the height of the concrete right cylinders, the weight of the cylinders (1200 pounds) must be converted into volume using the density of concrete (150 pounds per cubic foot). The correct volume formula is V = weight/density, which gives V = 1200 lbs / 150 lbs/ft³ = 8 ft³. Using the volume formula for a cylinder, V = πr²h, and substituting the radius (4 inches or 1/3 feet), the height can be calculated. The final height of each cylinder is approximately 22.96 feet. Understanding the relationship between weight, density, and volume is crucial for accurate calculations.
Meadow Delorto
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Homework Statement


I have to construct 8 concrete right cylinders for hurricane protection on windows, but I need to know the height to fit the given criteria. Each has a 4 inch radius and each weighs 1200 pounds. Concrete weighs 150 pounds per cubic foot.

V= volume of right cylinder
r=radius
h= height of right cylinder

Homework Equations


V=pi*r^2*h

The Attempt at a Solution


V=pi*r^2*h
1200 lbs= pi*16*h
h=23.8732 inches (1’11.87”).

I just don’t know where the weight of concrete, 150 pounds per cubic foot, comes into play. Thank you very much.
 
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:welcome:You need to work in feet, not inches, and the equation you are missing is ## W=\delta \, V ##, where ## \delta ## is the density in pounds per cubic foot. When you compute the volume, the radius ## r ## needs to be converted to "x" feet. The answer you get for height ## h ## will be in feet.
 
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In your statement, you set V=1200 pounds. That is not right; ##V=\frac{weight}{density}##. The density is what give is 150 pounds per cubic foot.
 
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Charles Link said:
:welcome:You need to work in feet, not inches, and the equation you are missing is ## W=\delta \, V ##, where ## \delta ## is the density in pounds per cubic foot. When you compute the volume, the radius ## r ## needs to be converted to "x" feet. The answer you get for height ## h ## will be in feet.
Would I be correct if I said it would have to be 22.96 feet?
 
Meadow Delorto said:

Homework Statement


I have to construct 8 concrete right cylinders for hurricane protection on windows, but I need to know the height to fit the given criteria. Each has a 4 inch radius and each weighs 1200 pounds. Concrete weighs 150 pounds per cubic foot.

V= volume of right cylinder
r=radius
h= height of right cylinder

Homework Equations


V=pi*r^2*h

The Attempt at a Solution


V=pi*r^2*h
1200 lbs= pi*16*h
h=23.8732 inches (1’11.87”).

I just don’t know where the weight of concrete, 150 pounds per cubic foot, comes into play. Thank you very much.

If the final object weighs 1200 lb and concrete weighs 150 lb/cu.ft., how many cubic feet of concrete does the object consist of? So, what is the object's volume, in cubic feet?
 
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You have the volume formula, and you know how much concrete and you have the density. So?

Convert 1200 pounds into the quantity in cubic feet.
Now use your volume formula to calculate the unknown height.
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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