Find the initial speed of jump using range and max height

AI Thread Summary
To find the initial speed of the dog during its jump, the key equations involve the maximum height (H) and horizontal distance (L). The vertical component of velocity at maximum height can be calculated using the equation Voy = √(2gH). The horizontal component of velocity needs to be determined by relating time to the horizontal distance traveled. By setting up equations for both the x and y directions and eliminating time, the complete solution can be derived. This approach will yield the initial speed without using trigonometric functions.
cosmo1993
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Homework Statement


A dog jumps a distance, L, and a maximum height, H, where the dog only has horizontal velocity when it travels through the hoop. What is the speed of your dog when he leaves the ground?
What is the speed of your dog when he goes through the loop? Both answers should NOT be in terms of sinθ or cosθ.
Max height = H
Distance = L
V at max height = Vx


Homework Equations


V^2 = Vo^2 + 2gΔH
V = (Vox^2+Voy^2)^.5

The Attempt at a Solution


0 = Voy^2 +2gH
Voy = square root(2gH)

My problem is I do not know how to find the horizontal component of velocity in order to solve the rest of the problem. I would greatly appreciate any help.

ps sorry for the bad formatting, this is my first time one the site.
 
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hi cosmo1993! welcome to pf! :smile:

(try using the X2 button just above the Reply box :wink:)

let t be the time it reaches the hoop

write the equations for the x and y directions that involve t

then eliminate t

show us what you get :smile:
 
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