Find the limit of the given sequence

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Homework Statement


Find the limit of the given sequence as n →∞

Homework Equations


(1+n^2)^(1/ln(n))

The Attempt at a Solution


Wolfram said the answer was e^2, though i cannot figure out why. Any help would be greatly appreciated.
 
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whattheheckV said:

Homework Statement


Find the limit of the given sequence as n →∞

Homework Equations


(1+n^2)^(1/ln(n))

The Attempt at a Solution


Wolfram said the answer was e^2, though i cannot figure out why. Any help would be greatly appreciated.
What have you tried ?
 
SammyS said:
What have you tried ?

lim (1+n^2)^(e/eln(n))
n→∞

lim (1+n^2)^e
n→∞
 
whattheheckV said:
lim (1+n^2)^(e/eln(n))
n→∞

lim (1+n^2)^e
n→∞
What the heck !

How about e^(ln( the limit ))

ln of the limit is limit of ln .

What is ##\displaystyle\ \ln\left( (1+n^2)^{1/\ln(n)}\right) \ ?##
 
whattheheckV said:
lim (1+n^2)^(e/eln(n))
n→∞

lim (1+n^2)^e
n→∞
Is the outer exponent above ##\frac e {eln(n)}##? If so, how did you go from and exponent of ##\frac e {eln(n)}## to an exponent of e? If you "cancel" the factors of e you would be left with an exponent of ##\frac 1 {ln(n)}##, which gets you right back to where you started.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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