Find the phase difference in terms of d, lambda, theta

AI Thread Summary
The path difference between the two waves in figure 4.8 is expressed as d*sin(theta). This approximation holds true when d is much smaller than x. The phase difference can be calculated using the formula (d*sin(theta)*2*pi)/lambda. This relationship is confirmed as correct within the context of the discussion. Understanding these concepts is crucial for analyzing wave interference patterns.
joelkato1605
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Homework Statement
Referring to Figure 4.8, what is the phase difference φ between S¯1 and S¯2 in terms of d,
θ and λ.
Relevant Equations
See attached image.
So in figure 4.8 the path difference between the two waves is d*sin(theta), then is the phase difference just (d*sin(theta)*2*pi)/lambda?
 

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joelkato1605 said:
So in figure 4.8 the path difference between the two waves is d*sin(theta)
This is a good approximation for the path difference when ##d << x##.

then is the phase difference just (d*sin(theta)*2*pi)/lambda?
Yes
 
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