Find the potential gravitational and kinetic energy of a ball after 0.4 seconds

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SUMMARY

The discussion focuses on calculating the potential gravitational and kinetic energy of a 3.0 kg metal ball dropped from a height of 3.5 meters after 0.4 seconds. The potential energy (EP) is calculated using the formula EP = mgh, resulting in 102.9 J. The kinetic energy (EK) requires the velocity of the ball after 0.4 seconds, which is derived from kinematic equations, rather than using acceleration directly. The correct approach involves determining the distance fallen and the speed gained during the fall to accurately compute the kinetic energy.

PREREQUISITES
  • Understanding of gravitational potential energy (EP = mgh)
  • Knowledge of kinetic energy formula (EK = 1/2mv^2)
  • Familiarity with kinematic equations for falling objects
  • Basic physics concepts related to motion and energy
NEXT STEPS
  • Study kinematic equations for uniformly accelerated motion
  • Learn how to calculate the velocity of falling objects after a specific time
  • Explore the relationship between potential and kinetic energy in free fall
  • Practice problems involving energy conservation in gravitational fields
USEFUL FOR

Students studying physics, educators teaching energy concepts, and anyone interested in understanding the dynamics of falling objects and energy transformations.

Darth Poison
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Homework Statement



A 3.0 kg metal ball is held 3.5m above the ground. Find the potential gravitational and kinetic energy of the ball after it is let go and has fallen for 0.4s


Homework Equations



EK= 1/2mv^2

EP=mgh



The Attempt at a Solution



Okay I know how to find both the kinetic and potential energy, but how does the time effect it? Is there a certain equation I have to sub it in other than the ones given. Please help :)

Potential= EP=mgh
Ep=(3.0Kg)(9.8m/s^2)(3.5m)
EP= 102.9 J

Kinetic = EK=1/2mv^2
EK=1/2(3.0kg)(9.8m/s^2)
EK=14.7 J
 
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Darth Poison said:

Homework Statement



A 3.0 kg metal ball is held 3.5m above the ground. Find the potential gravitational and kinetic energy of the ball after it is let go and has fallen for 0.4s


Homework Equations



EK= 1/2mv^2

EP=mgh



The Attempt at a Solution



Okay I know how to find both the kinetic and potential energy, but how does the time effect it? Is there a certain equation I have to sub it in other than the ones given. Please help :)

Potential= EP=mgh
Ep=(3.0Kg)(9.8m/s^2)(3.5m)
EP= 102.9 J

Kinetic = EK=1/2mv^2
EK=1/2(3.0kg)(9.8m/s^2)
EK=14.7 J

It would seem you actually don't know how to find KE.

You have substituted an acceleration value in for the velocity.

The 0.4 seconds is there as in that time the object will have fallen some distance [so you won't use 3.5 in the PE formula], and will have gained some speed - the value of which you will use in the KE formula.

Normal kinematics for falling objects is used to find the distance and speed values.
 


PeterO said:
It would seem you actually don't know how to find KE.

You have substituted an acceleration value in for the velocity.

The 0.4 seconds is there as in that time the object will have fallen some distance [so you won't use 3.5 in the PE formula], and will have gained some speed - the value of which you will use in the KE formula.

Normal kinematics for falling objects is used to find the distance and speed values.



Thank you for helping me realize that, I appreciate it. :D
 

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