- #1
- 38
- 5
- Homework Statement
- I am supposed to find the equivalent to R2 and I got 2, but I am supposed to get 3
- Relevant Equations
- None
berkeman said:It's pretty hard for me to read your uploaded pictures. Can you post a better picture of the original circuit, and type some of your work into the forum so it's readable? Thanks.
the circuit:berkeman said:Welcome to PF.
It's pretty hard for me to read your uploaded pictures. Can you post a better picture of the original circuit, and type some of your work into the forum so it's readable? Thanks.
(you should consider learning to post math using LaTeX -- see the "LaTeX Guide" link below the Edit window)
It's at the beginning of the threadphinds said:How could we possibly know where you went wrong when you have not shown your work ???
SHOW EVERY STEP
Yes, and it got this response:Edy56 said:It's at the beginning of the thread
TYPE your work into the thread.berkeman said:It's pretty hard for me to read your uploaded pictures. Can you post a better picture of the original circuit, and type some of your work into the forum so it's readable? Thanks.
That's what I did here?Edy56 said:the circuit:
View attachment 321978
here is what I did:
(english is not my first language so sorry if i get any terms wrong)
I thought R3, R4 and R5 form a triangle so I turned it into a star for easier calculation and I did the same for R6 R7 and R1.
Then I thought R34 and R35 are parallel so I calculated that too and the same I did for R61 and R71.
Then I thought all of them were connected in order meaning I could add them all together.
That is:
R3435 +R45 + R67 + R6171.
I got the answer 2, I need to get 3.
Where did I go wrong?
No, you listed the steps you did not show any of the calculations.Edy56 said:That's what I did here?
I am not sure as to how write that. I can draw it, but I don't know how to write those steps.phinds said:No, you listed the steps you did not show any of the calculations.
THIS:
"I thought R3, R4 and R5 form a triangle so I turned it into a star for easier calculation and I did the same for R6 R7 and R1."
is a set of steps. It is not calculations.
Okayphinds said:I'm sure you could figure out how to type numbers and equations, but I can see that it would be a lot of work. Perhaps someone else here will be willing to look at your hand-written work and follow it to see if they can find your error.
Baluncore said:I cannot read the component values.
View attachment 321988
I am not sure I understand...Baluncore said:You do not need the Y to Δ transform.
Current source Ig is infinite resistance, so remove it from the circuit.
Voltage sources, E1 and E2 are zero resistance, so short them.
R1 = R5 = R6 = 2k;
R3 = R4 = 1k;
R7 = 4k.
Series; +
Parallel; //
R16 = R1 + R6 =
R34 = R3 + R4 =
R167 = R16 // R7 =
R345 = R34 // R5 =
R2 = R167 + R345 = 3k.
Yes, you can do it in the longer way using the inverse Y to Δ transform;Edy56 said:Why isn't it like that?
The resistance R in a network is a measure of how much the network impedes the flow of electricity. It is important to know the resistance in order to properly design and analyze electrical circuits.
The resistance R in a network can be calculated using Ohm's Law, which states that resistance is equal to the voltage divided by the current. It can also be calculated using the formula R = V/I, where V is the voltage and I is the current.
The resistance R in a network is affected by several factors, including the material of the conductors, the length and cross-sectional area of the conductors, and the temperature of the conductors. Additionally, the presence of resistors or other components in the network can also affect the overall resistance.
The arrangement of components in a network can affect the overall resistance R in a few ways. For example, connecting resistors in series will increase the overall resistance, while connecting them in parallel will decrease the overall resistance. Additionally, the placement of resistors in relation to other components can also affect the resistance.
There are several methods for measuring the resistance R in a network, including using a multimeter, a Wheatstone bridge, or a digital ohmmeter. Each method has its own advantages and may be more suitable for different types of networks or situations.