Find the second force in unit-vector notation

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To find the second force acting on a 1.6 kg box experiencing a 20 N force to the right and an acceleration of 12 m/s² at 30 degrees, the solution requires calculating the net force using Newton's second law. The first force is represented as 20 N in the positive x-direction, while the second force must be determined in unit-vector notation. The attempted solution provided values of -26 and -10.34, which were criticized as incomplete answers rather than a full solution. The discussion emphasizes the need for a clear methodology to arrive at the correct force values. Proper calculations and vector analysis are essential for solving the problem accurately.
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Homework Statement



There are two forces on the 1.6 kg box
20 n to the right
12m/s2 acceleration at 30 degress going from the origin into the 3 quadrin

Find the second force in unit-vector notation.
( N) i + ( N) j
(b) Find the second force as a magnitude and direction.
N, ° (counterclockwise from the +x-axis is positive)

Homework Equations







The Attempt at a Solution



-26, -10.34
 
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tjcreamer9 said:

The Attempt at a Solution



-26, -10.34
This isn't a solution, its a set of answers. I think you'll be hard pushed to get someone to work through the problem themselves to check your answers.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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