Find Shear Stress in Shaft Design | Modulus of Rigidity 80kN/mm2

AI Thread Summary
In shaft design, a common guideline dictates that the angle of twist should not exceed 1° over a length equal to 20 times the shaft's diameter. Given a modulus of rigidity of 80 kN/mm², the discussion seeks to determine the corresponding shear stress in the material. Participants express challenges in solving the problem due to having two unknowns. The request emphasizes the need for a structured approach using the HW Template to clarify attempts at finding a solution. Ultimately, the discussion aims to resolve the relationship between shear stress and the specified design constraints.
loststudent123
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A rule often used in shaft design states that the angle of twist shall not exceed 1 on a length equal to 20 diameters. What stress in the material does this imply if the modulus of rigidity is equal to 80 × 103 N/mm2 ?
was wondering if anybody had an insight on how to do this ?

have tried a few ways but keep being left with 2 unknowns
 
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Please use the HW Template and fill out all three sections, including the one which includes your attempts at solution.
 
Thread 'Have I solved this structural engineering equation correctly?'

Thread 'Have I solved this structural engineering equation correctly?'

Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...
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