Find the Solve the Problem with Force!

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To solve the problem of work done on a box weighing 200N sliding 20m on a rough track with a friction coefficient of 0.2, it is essential to consider the angle at which the force is applied. The effective force acting on the box is the applied force multiplied by the cosine of the angle. If the friction coefficient is kinetic, the force of friction can be calculated as the coefficient multiplied by the box's weight, allowing for the determination of work done against friction. However, if the coefficient refers to static friction, the problem cannot be solved without knowing if the applied force is sufficient to overcome static friction. Understanding these dynamics is crucial for accurately calculating the work done.
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Answer Problem!

A BOX WEIGHIN 200N IS 2 B SLID SLOWLTHROUGH 20 M ON A ROUGH STRAIGHT TRACKFRICTION COEFF=O.2I HAV 2 FIND THE WORK DONE BY THE FORCE ACTIN ON THE BOX!IF THE FORCE ACTS AT AN ANGLE 'A'WITH THE HORIZONTAL!
I CANT GET THE ANSWER!
 
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Please tell us your thoughts on the problem, and what you have come up with so far.

- Warren
 
W = Fd

The force must be parallel with the displacement! F is not the total force applied to the box. F is actually the force applied * cos(\theta).
 
Last edited:
ok... unless u know the angle A i doubt this problem can be solved... most prolly the coef. of friction is coef. of kinetic friction... so then the force of friction is (coef.)*mass*g and so the work done by it is distance*force of friction (jsut as shawn said). But if the coef. of friction is static friction, then this problem can't be solved. coz the work done by friction cud be 0 if the applied force is insufficient to move the block
 

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