Find the spectrum of the 2nd excited states.

In summary, to find the spectrum of the 2nd excited states, the value of the mass squared, the condition for the state to be physical, and the gauge symmetry transformation due to null states, you should break down the given state and use relevant principles and equations from quantum mechanics and particle physics to solve each component. Don't be afraid to consult resources and approach the problem systematically.
  • #1
rbwang1225
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Homework Statement


A state at the 2nd exited level is of the form:
##|\epsilon>=(\epsilon_{\mu\nu}\alpha^\mu_{-1}\alpha^\nu_{-1}+\epsilon_{\mu}\alpha^\nu_{-2})|0;p>##
Find the spectrum of the 2nd excited states, the value of the mass squared, the condition for the state to be physical, and the gauge symmetry transformation due to null states.

Homework Equations


I don't know much.

The Attempt at a Solution


Any advice would be appreciated!
 
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  • #2


I would suggest starting by breaking down the given state into its components and understanding what each term represents. The notation may seem intimidating, but it is important to understand the physical meaning behind it.

Next, I would suggest using the appropriate equations and principles from your knowledge of quantum mechanics and particle physics to derive the spectrum of the 2nd excited states and the value of the mass squared. This may involve manipulating the operators and using commutation relations.

To determine the condition for the state to be physical, you may need to consider the constraints on the state imposed by the theory. This could involve looking at the gauge symmetry and any conservation laws that apply.

Finally, to understand the gauge symmetry transformation due to null states, you may need to investigate the concept of null states and how they affect the physical states in the theory. This could involve looking at the generators of the gauge symmetry and how they act on the state.

Overall, my advice would be to approach this problem systematically, breaking it down into smaller parts and using your knowledge and understanding of the relevant principles and equations to solve each part. Don't be afraid to consult textbooks or other resources for guidance. Good luck!
 

1. What is the meaning of "2nd excited state" in finding the spectrum?

The "2nd excited state" refers to the energy level of an atom or molecule that has been excited by absorbing energy, typically through exposure to light or heat. It is the second highest energy level that an electron can occupy within an atom or molecule.

2. How is the spectrum of the 2nd excited state different from the 1st excited state?

The spectrum of the 2nd excited state is different from the 1st excited state because the electrons are in different energy levels. This means that the wavelengths of the light emitted or absorbed by the atom or molecule will also be different, resulting in a different spectrum.

3. Can the 2nd excited state be observed in all atoms and molecules?

Yes, the 2nd excited state can be observed in all atoms and molecules. However, the specific energy level and resulting spectrum will vary depending on the atomic or molecular structure and the amount of energy absorbed.

4. How is the spectrum of the 2nd excited state determined?

The spectrum of the 2nd excited state is determined through spectroscopy, which involves analyzing the wavelengths of light emitted or absorbed by the atom or molecule. This can be done through techniques such as absorption spectroscopy or emission spectroscopy.

5. What is the significance of finding the spectrum of the 2nd excited state?

Finding the spectrum of the 2nd excited state can provide valuable information about the energy levels and structure of atoms and molecules. This can be useful in fields such as chemistry and astrophysics, where understanding the behavior of atoms and molecules is crucial in studying chemical reactions and the composition of celestial objects.

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