Find the Thevenin's Equivalent for the following circuits

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SUMMARY

The discussion focuses on finding Thevenin's Equivalent for specific circuit problems. The participants confirm that the Thevenin resistance is correct, but there is an error in calculating the Thevenin voltage due to a sign drop when solving for the current i2. The correct Thevenin voltage is approximately 20.0 V, achieved by using more precise intermediate values. Additionally, participants emphasize the importance of posting each problem separately to avoid confusion and recommend uploading images directly instead of using external links.

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AlphaLibrae
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Homework Statement
3) Find the Thevenin equivalent of the following circuit: i.e. find the thevenin's voltage and thevenin's resistance

4)Find the Thevenin's voltage and Thevenin's resistance for the following circuit and hence find the current through the load resistor

The problems and the circuit diagrams are here:
Relevant Equations
Kirchhoff's Laws
The current entering any junction is equal to the current leaving that junction. i2 + i3 = i1 + i4

The directed sum of the potential differences (voltages) around any closed loop is zero.
v1 + v2 + v3 +v4 = 0
I have actually already written out and solved for my own solutions to these problems, but I was wondering if I could get a second opinion on my solutions:

For Problem 3:
For Problem 4:
 
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In future, please post each problem in separate posts. This is PF policy. We find that this avoids "crosstalk" confusion when multiple people are engaged with different problems in the same thread.

For your first problem the Thevenin resistance looks okay but the Thevenin voltage does not. I think you've dropped a sign when solving for ##i_2##.
 
gneill said:
In future, please post each problem in separate posts. This is PF policy. We find that this avoids "crosstalk" confusion when multiple people are engaged with different problems in the same thread.

For your first problem the Thevenin resistance looks okay but the Thevenin voltage does not. I think you've dropped a sign when solving for ##i_2##.

Ah ok, so would it actually be 15 + (6)(0.83 = 19.98 V?
 
AlphaLibrae said:
Ah ok, so would it actually be 15 + (6)(0.83 = 19.98 V?
Yes. With a few more digits used for intermediate values you'd find out that it comes out to 20.0 V.
 
gneill said:
In future, please post each problem in separate posts.
... and please upload photos instead of link to another provider, because otherwise it happens what just [2/22/20 - 1426 GMT] happened: "imgur refuses to connect" or the link will be broken long term!
 
fresh_42 said:
... and please upload photos instead of link to another provider, because otherwise it happens what just [2/22/20 - 1426 GMT] happened: "imgur refuses to connect" or the link will be broken long term!
Can't see a thin.
 

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