Find the True Statement About Dot Product of Two Vectors

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Homework Help Overview

The discussion revolves around the properties of the dot product of two vectors, specifically focusing on determining which statements about the conditions for a dot product of -1 are true.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants analyze the implications of the dot product formula and the conditions under which it can yield a negative result. They explore the relationship between the angle between vectors and the sign of the dot product, considering which statements can be eliminated based on reasoning about angles and magnitudes.

Discussion Status

Some participants have provided reasoning that leads to the elimination of certain options based on the properties of the cosine function and the angle ranges that produce a negative dot product. There is an ongoing exploration of the remaining options, with some participants suggesting that option C may be the correct choice.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information available for discussion. The original poster has already eliminated one option and is seeking further clarification on the remaining statements.

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Homework Statement



The dot product of.two vectors is -1which of the following statements is true

A. They must be unit vectors pointing in opposite directions.
B. They must be unit vectors pointing j. The same direction.
C. They must be more than 90( and less than 270 )degrees from each other.
D. They must be perpendicular to each other.
E. They must sum to zero

Homework Equations


I have eliminated D though I find the others difficult

The Attempt at a Solution

 
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A.B = |A||B|cosθ .So we are looking at the product of three quantities whose product is -1 .Two quantities are magnitudes ,hence positive.Now only cosθ term can be negative .

Now rethink about the options .A few of them can be eliminated .
 
\vec{u}\circ\vec{v}=|\vec{u}|\cdot|\vec{v}|\cos\angle(\vec{u},\vec{v})=-1\Rightarrow<br /> \cos\angle(\vec{u},\vec{v})&lt;0\Rightarrow 90^o&lt;\angle(\vec{u},\vec{v})&lt;270^o
the same direction: \cos\angle(\vec{u},\vec{v})=\cos 0^o=1\Rightarrow \vec{u}\circ\vec{v}\ge 0&gt;-1 so not B

2i\circ\left(-\frac{1}{2}i\right)=-1
so not A nor E
 
Tanya Sharma said:
A.B = |A||B|cosθ .So we are looking at the product of three quantities whose product is -1 .Two quantities are magnitudes ,hence positive.Now only cosθ term can be negative .

Now rethink about the options .A few of them can be eliminated .


Ok so in order to obtain a negative value the value of the angle would have to be between 90 and 270 then this leaves option ' c' is that so?
 
Correct ...
 

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