Find the volume of the solid formed by the rotation around the y=0

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Homework Help Overview

The discussion revolves around finding the volume of a solid formed by rotating a function, specifically y=|sin(2x)*cos(2x)|, around the line y=0. Participants are examining the setup and limits of integration for the problem.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the correctness of the integral and the limits of integration, questioning whether the integration should be from 0 to π/2 or from 0 to π. There is also mention of the function being zero at certain points.

Discussion Status

The discussion is ongoing with participants clarifying the limits of integration and addressing potential mistakes in the setup. Some guidance has been offered regarding the integral's correctness, but no consensus has been reached on the final approach.

Contextual Notes

There is a mention of a correction needed regarding the limits of integration, indicating that the original poster initially misinterpreted the range for integration.

Michael_0039
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Homework Statement
Find the volume of the solid formed by the rotation around the y=0
y=|sin(2x)*cos(2x)|
Relevant Equations
nil
Hi,

I find this...
picpic.png


Please tell me your opinion on this.

Thanks.
 
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Michael_0039 said:
Homework Statement: Find the volume of the solid formed by the rotation around the y=0
y=|sin(2x)*cos(2x)|
Homework Equations: nil

Hi,

I find this...
View attachment 252926

Please tell me your opinion on this.

Thanks.
The integral itself looks right, although the graph of that function is zero at ##\pi/4##.

Did the question say to integrate from ##0## to ##\pi/2##?
 
PeroK said:
The integral itself looks right, although the graph of that function is zero at ##\pi/4##.

Did the question say to integrate from ##0## to ##\pi/2##?
Oops my mistake, it is: 0 ≤ x ≤ π

I have to fix it.

Thanks
 
So integrate from 0 to π: V=(π^2)/8
 

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