Find V(o) / V(s) in Output Opamp Voltage

Therefore, for an AC source, the gain for V(o) / V(s) will depend on the frequency of the input signal. In summary, for the given circuit, with capacitors acting as open circuits in DC conditions, V(o) will be equal to 0V and the gain for V(o) / V(s) will depend on the frequency of the input signal assuming it is an AC source.
  • #1
Abdulwahab Hajar
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2

Homework Statement


In the figure below find V(o) / V(s)

Homework Equations


In an opamp current doesn't enter through the inverting and non-inverting terminals, furthermore in DC conditions a capacitor acts like an open circuit

The Attempt at a Solution


The way I see it, both capacitors will act like open circuits current will have no path to follow...
therefore V(o) will be equal to 0V. also, no initial conditions are mentioned...
Is this correct?
or could this be done by a laplace transform??
figure is attached
Thank you
 

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  • #2
Assume that ##v_s(t)## is an AC source. The gain will depend upon the frequency.
 
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  • #3
gneill said:
Assume that ##v_s(t)## is an AC source. The gain will depend upon the frequency.
Got it, but how can I tell when it's an AC from a DC source
 
  • #4
Abdulwahab Hajar said:
Got it, but how can I tell when it's an AC from a DC source
Usually they will use a slightly different symbol for the source.

upload_2017-5-8_14-52-28.png


In this case the presence of capacitors in the feedback path is a strong indication that some sort of signal filter is implemented, implying an AC input signal.
 
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