Find value of a and b such that F(x) is a valid cumulative distribution function

chessmath
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Hi
I have a question , the question asks find value of a and b such that F(x) is a valid cumulative distribution function?

1-a*exp(-x/b) x≥0
F(x)=
a*exp(x/b) x<0

My attempt to solve the problem:

I know F(x) when x goes to ∞ in 1 and when x goes to -∞ is 0. also I know F(x) should be right continuous and it is non-negative. However, non of them help me to find even one of the constants, any help will be appreciated ?
 
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chessmath said:
Hi
I have a question , the question asks find value of a and b such that F(x) is a valid cumulative distribution function?

1-a*exp(-x/b) x≥0
F(x)=
a*exp(x/b) x<0

My attempt to solve the problem:

I know F(x) when x goes to ∞ in 1 and when x goes to -∞ is 0. also I know F(x) should be right continuous and it is non-negative. However, non of them help me to find even one of the constants, any help will be appreciated ?

If you want it to be continuous at x=0 what are the limits of both forms of F as x->0? Though actually if you only have right continuous, I don't think you have that restriction. Hmm. Not sure. I can see some restrictions on the values of a and b, but not how to calculate them.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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