Find Value of I in Ohm's Law Circuit

AI Thread Summary
The discussion focuses on calculating the current (I) in a circuit using Ohm's Law (V = IR). The user calculates the equivalent resistance (R_eq) as 7.6 ohms and determines the current to be 0.526 amperes. However, they express confusion about why their answer is not among the provided options and question the omission of the top resistor in their calculations. Clarification is sought regarding the treatment of the two 4-ohm resistors in parallel and the wire with zero resistance. The conversation highlights the importance of accurately accounting for all components in circuit analysis.
22990atinesh
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Homework Statement


In the circuit shown the value of I in ampere is
[img=http://s28.postimg.org/5adobnb95/Capture.jpg]

Homework Equations


## V = I R ##

The Attempt at a Solution


Leaving 4 ohm above resistor Equivalent R will be
##R_{eq} = \frac{4*4}{4+4} + 4 + 1.6 = 7.6##
##I = \frac{V}{R}##
## I = \frac{4}{7.6} = 0.526 ##
Ans is not given in the option please tell what I'm doing wrong
 
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Why do you think you can ignore the top resistor?

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