Find Velocity at Point B: Dynamics Problem Solving

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To find the velocity of a 600lb motorcycle traveling 500 ft from point A to point B, the force exerted on the motorcycle is given by F(t)=300(1-.1t). The discussion emphasizes using Newton's second law (F=ma) to derive acceleration as a function of time, which can then be integrated to find velocity. It is noted that the formula Vi^2=Vf^2+2A(500) is inappropriate for this scenario due to the non-constant acceleration. Instead, the correct approach involves using integral relationships between acceleration, velocity, and distance. Understanding these dynamics is crucial for solving the problem effectively.
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this is a part of a much bigger problem, I have a 600lb motorcycle going from point A to point B, which are 500 ft apart, i know the force exerted by the road on the motorcycle when the throttle is pressed is F(t)=300(1-.1t).
I need time in order velocity at B ,
I'm really lost on where to start on this, i was thinking f=ma could give me acceleration, but then i don't know what to do with that.
 
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Are you trying to determine the velocity at point B?

If you know the acceleration then by definition you should be able to get the velocity.
 
so f=ma will give me a acceleration as a function of t, and yes i need velocity at B, but then won't i only have velocity as a function of t if by definition?.
 
Right, but if you have velocity, you can find position. Find how long it takes to get to point B, then use that t for your velocity.
 
phyziks4lyfe said:
this is a part of a much bigger problem, I have a 600lb motorcycle going from point A to point B, which are 500 ft apart, i know the force exerted by the road on the motorcycle when the throttle is pressed is F(t)=300(1-.1t).
I need time in order velocity at B ,
I'm really lost on where to start on this, i was thinking f=ma could give me acceleration, but then i don't know what to do with that.

Gee, if only there were a way that acceleration could be used to get velocity, and that velocity could then be used to find distance. It would seem to be a good reason to study rectilinear motion in physics, or something. Maybe somebody wrote a textbook on how to do this stuff. IDK, that would probably take a lot of work to figure out.
 
so would i use Vi^2=Vf^2+2A(500) and substitute in V and A as their function of t equations? because then i get t= 10.05 does that seem right?
 
What units are you using for m, F, and distance? I hope F is in ft/lbs.
 
m = slugs, F lbs, distance = ft
 
phyziks4lyfe said:
so would i use Vi^2=Vf^2+2A(500) and substitute in V and A as their function of t equations? because then i get t= 10.05 does that seem right?
No, that formula only works for constant acceleration. You need to use the general relationships between acceleration, velocity, and distance - namely, integral formulas.
 
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