Find Wavelengh - Young't Double Slit

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    Double slit Slit
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The discussion revolves around calculating the wavelength of light from a discharge lamp using the double-slit experiment formula. The provided values include a perpendicular distance of 2.35 cm from the midpoint of the slits, a slit-to-screen distance of 1.2 m, and a slit separation of 0.03 mm. The calculated wavelength is approximately 5.875 x 10^-7 m, which is within the range of visible light. Participants noted potential issues with significant figures but confirmed the calculation's validity. Overall, the solution aligns with expectations for wavelengths of visible light.
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Homework Statement


For light from a discharge lamp, the first-order bright fringe is observed at a perpendicular distance of 2.35cm from the mid-point of the slits, when the slit-to-screen distance is 1.2m and the slit separation is 0.03mm. What is the wavelengh of the light from the lamp?


Homework Equations


Wavelength = xd/D


The Attempt at a Solution


x = 0.0235m, d = 0.00003m, D = 1.2m

Wavelength = xd/D = (0.0235x0.00003)/1.2 = 7.05x10^-7/1.2 = 5.875x10^-7m


Not quite sure where I've gone wrong ..or if I was even on the right path. If you could offer some assistance it would be much appreciated :) (p.s. hi, nice forum ^^)
 
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Welcome to Physics Forums, :smile: and sorry about the late reply.

There might be an issue with the number of significant figures in your answer, but other than that it looks correct to me. Why do you think it is wrong?
 
I had the wrong figures in my head for the wavelength of visible light. My answer fits in there quite comfortably as it happens.

Thanks for your reply ..and thanks for your welcome too. Long time lurker, first time poster :smile:
 
Cool, glad it worked out.
 
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