Find Weight of Object Pulled by Rope w/ FT=30N & Acceleration=1.4m/s2

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To find the weight of an object being pulled by a rope with a tension of 30N and an upward acceleration of 1.4 m/s², the equation FT = mg + ma is used. The correct approach involves recognizing that the net force equals the sum of the tension and the weight of the object. The calculation shows that the weight of the object should be 3.6 kg, as per the book's method. The confusion arises from misinterpreting mass and weight, as well as the direction of acceleration. Clarifying these concepts is essential for accurate problem-solving in physics.
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An object is pulled up by a rope from an elevator traveling upward with an acceleration of 1.4 m/s2. The tension in the rope is 30N. What is the weight of the object.
A) 2.6kg
B) 3.6kg
C)4.6kg
D)5.6kg

My attempt:
FT=30N
asystem=1.4m/s2
Weight of object=mg

The system is accelerating up, so let 'up' be positive.
\SigmaF=ma

Sum of the forces acting upwards minus sum of the forces acting downward:
30N+(-mg)=ma
30N=m(a+g)
30/(9.8+1.4)=m
m=2.6kg

For some reason I am not getting the correct answer. The book says that it is 3.6kg. What am I doing wrong?

This is the method the book uses:
"Since the forces act in opposite directions, they are related as: mg=ma+T"
 
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looks like a double book error. 1.) Mass and weight are not the same. 2.) The acceleration and movement are not necessarily in the same direction, and this is not stated. Assuming that the acceleration is upward, what is the object's weight?
 
If the acceleration is upward and they are talking about mass, did I do it correctly?
 
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