Find work from additional spring compression

AI Thread Summary
To calculate the work done in compressing a spring with a spring constant of k=35000 N/m by 0.10 m, the formula U=1/2*k*x^2 yields 175 J. For compressing the spring an additional 0.10 m, the total compression becomes 0.20 m, resulting in a total work of 700 J. To find the additional work required for this second compression, the correct approach is to subtract the initial work from the total work, leading to an additional 525 J. The discussion clarifies the importance of understanding how to apply the spring work formula correctly for incremental compressions. This highlights the need to differentiate between total and additional work when dealing with spring compression.
Sneakatone
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The spring used has a spring constant of k= 35000 N/m.
a) how much work must you do to compress this spring by 0.10 m from its relaxed condition.
U=1/2*k*x^2
.5*35000*(0.1)^2=175 J (correct)

b)how much work must you do to compress the spring an additional 0.10 m?
I tried the same equation but with x=0.2 but it doesn't work. (U=700J)
 
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Sneakatone said:
b)how much work must you do to compress the spring an additional 0.10 m?
I tried the same equation but with x=0.2 but it doesn't work. (U=700J)
I assume they want how much additional work you must do.
 
Ohhh
I subtracted 700-175 and its correct , Thanks!
 

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