Finding Acceleration Using a Table: Small Graphing Question | Homework Help

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To find acceleration from the provided table, the slope of the line of best fit for the displacement versus time squared graph is essential. The user encounters difficulties adding error bars for the x-axis in Excel and questions whether including the origin point (0,0) would affect the slope calculation. The equation s = 1/2 a * t^2 relates displacement to acceleration, guiding the analysis. Including the origin could skew results since the experiment did not measure displacement at zero seconds. The discussion emphasizes the importance of accurately representing data in graphing to determine the correct acceleration.
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Homework Statement



I have a question for a graph where I'm basically trying to find the acceleration using a table which has a time squared value starting at 7.132 seconds squared and ending at 9.686 seconds squared. I need to find a regression (I need to find the slope for the line of best fit. This is the graph:

The first problem is the error bars. I got y error bars but when I click on format options for the excel graph, it doesn't show x bars options so how do I add error bars? And my other question is, how/should I add (0,0) to the graph because obviously the displacement is 0 m at 0 seconds but this wasn't conducted in the experiment so wouldn't it skew the slope of the line of best fit?

Homework Equations



Here's the relation:
y= mx + b --------> s(displacement) = 1/2 a(acceleration)*t^2(seconds squared)

and here's the table:

-(s)--------(t^2)
113.76-----7.132
123.56-----7.896
133.3------8.588
143.66-----9.321
152.9------9.686


The Attempt at a Solution



http://img106.imageshack.us/img106/2456/nettles1qb0.png
 
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Should I set 7.132 to be the x intercept?
 
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