Finding acceleration using velocity

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SUMMARY

The discussion revolves around calculating acceleration from a given velocity function for a race car starting from rest. The velocity is defined as vx(t) = (0.940 m/s³)t² for the first 5.0 seconds. The correct approach involves understanding the relationship between velocity, displacement, and acceleration. The final calculated acceleration is confirmed to be 7.46 m/s².

PREREQUISITES
  • Understanding of kinematic equations, specifically the relationship between velocity, displacement, and acceleration.
  • Familiarity with calculus concepts, particularly derivatives and integrals as they apply to motion.
  • Knowledge of basic physics principles related to motion in one dimension.
  • Ability to manipulate algebraic equations to solve for unknown variables.
NEXT STEPS
  • Study the derivation of kinematic equations in physics.
  • Learn about the relationship between velocity and acceleration in calculus.
  • Explore the concept of integration to find displacement from velocity functions.
  • Practice solving problems involving motion with variable acceleration.
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and motion analysis, as well as educators looking for examples of acceleration calculations from velocity functions.

Crusaderking1
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Homework Statement

A race car starts from rest and travels east along a straight and level track. For the first 5.0 s of the car's motion, the eastward component of the car's velocity is given by vx(t)=(0.940 m/s3)t2

Homework Equations



I think I am suppose to use the equation x-x0=(v0+v)/2)t

The Attempt at a Solution



I know the givens are x0=0 and t=5.00s, but I don't know how to use vx to solve for acceleration. Thanks.

You guys didn't happen to obtain7.46 m/s^2 as the answer, did you?
 
Last edited:
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Crusaderking1 said:
the car's velocity is given by vx(t)=(0.940 m/s3)t2I think I am suppose to use the equation x-x0=(v0+v)/2)t

No, that relation is valid between displacement and velocity for a special kind of motion, what is it? Is it the same as the motion in the problem?

Do you need to get the displacement or the acceleration?


Hint: how is velocity and displacement related in general? How is acceleration defined?

ehild
 
ehild said:
No, that relation is valid between displacement and velocity for a special kind of motion, what is it? Is it the same as the motion in the problem?

Do you need to get the displacement or the acceleration?


Hint: how is velocity and displacement related in general? How is acceleration defined?

ehild

ok thanks! I just figured it out. =)

the answer is 7.46 m/s^2.
 

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