Finding acceleration when mass and force are givern

AI Thread Summary
To find the acceleration of a rocket with a mass of 5.27*10^5 kg subjected to a force of 6.75*10^6 N, the equation F=ma is used. Rearranging this gives a = F/m, leading to the calculation of acceleration. It's important to consider that the rocket's weight, acting downward, affects the net force and thus the actual acceleration. The discussion highlights the need to account for both thrust and weight in determining the net force. Understanding these dynamics is crucial for accurately solving the problem.
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Homework Statement



What is the acceleration produced by a force of 6.75*10^6N on a rocket of mass 5.27*10^5kg.? F=6.75*10^6N ma= 5.27*10^5kg

Homework Equations



F=6.75*10^6N ma= 5.27*10^5kg



The Attempt at a Solution


F=ma
given F=6.75*10^6=
1000,000* 6.75
6.75*


Heck I am lost
 
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It's F_net =ma, or rearranging, a = F_net/m.

Presumably, the rocket is accelerating straight upwards, so you have to consider that it's weight acts straight down, thereby resulting in a net force that is less than the rocket's thrust force F.
 
Misread problem...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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