Finding all subsets of a list of positive integers using backtracking

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SUMMARY

The discussion centers on a Python 3 implementation for generating all subsets of a list of positive integers using backtracking. The provided code defines a function `subsets(nums)` that calls a helper function `backtrack(nums, start, curr)`, which recursively builds subsets and appends them to the `ans` list. The example list `[1, 2, 3]` produces the output `[[], [1], [1, 2], [1, 2, 3], [1, 3], [2], [2, 3], [3]]`. Participants emphasize the importance of understanding the code by stepping through it line by line, utilizing print statements or debugging tools.

PREREQUISITES
  • Familiarity with Python 3 syntax and functions
  • Understanding of recursion and backtracking algorithms
  • Basic knowledge of list operations in Python
  • Experience with debugging techniques in an IDE
NEXT STEPS
  • Study Python 3 recursion techniques in depth
  • Learn about backtracking algorithms and their applications
  • Explore debugging tools in IDEs for step-by-step code execution
  • Investigate the concept of power sets and their mathematical implications
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Software developers, particularly those working with algorithms, data structures, and Python programming, will benefit from this discussion. It is also valuable for educators teaching algorithm design and recursion concepts.

Andrew1235
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The following Python 3 code is provided as the solution to this problem (https://leetcode.com/problems/subsets/solution/) that asks to find all subsets of a list of integers. For example, for the list below the output is [[], [1], [1, 2], [1, 2, 3], [1, 3], [2], [2, 3], [3]].

I am not familiar with backtracking. Can someone explain how the code works?

alist = [1,2,3]

ans = []

def backtrack(nums, start, curr):

ans.append(curr)

for i in range(start, len(nums)):

backtrack(nums, i+1, curr + [nums])

def subsets(nums):
backtrack(nums, 0, [])
return ans

print(subsets(alist))
 
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Andrew1235 said:
The following Python 3 code is provided as the solution to this problem (https://leetcode.com/problems/subsets/solution/) that asks to find all subsets of a list of integers. For example, for the list below the output is [[], [1], [1, 2], [1, 2, 3], [1, 3], [2], [2, 3], [3]].

I am not familiar with backtracking. Can someone explain how the code works?

Python:
alist = [1,2,3]

ans = []

def backtrack(nums, start, curr):
 
    ans.append(curr) 
    
    for i in range(start, len(nums)):
 
        backtrack(nums, i+1, curr + [nums[i]])

def subsets(nums):     
    backtrack(nums, 0, [])
    return ans
   
print(subsets(alist))
You need to put
Python:
[/color] before your code and
[/color] afterwards if you want it to be readable.

Python:
alist = [1,2,3]
ans = []

def backtrack(nums, start, curr): 
    ans.append(curr)     
    for i in range(start, len(nums)): 
        backtrack(nums, i+1, curr + [nums[i]])

def subsets(nums):     
    backtrack(nums, 0, [])
    return ans
   
print(subsets(alist))
 
Last edited by a moderator:
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Andrew1235 said:
I am not familiar with backtracking. Can someone explain how the code works?
The best (only?) way to understand it is to work through it line by line. You can do this on paper, or by inserting print statements in the code, or by using the 'watch' facitilty of an IDE and stepping through the code.
 
What pbuk said. At the very least, adding
Python:
print("backtrack called with)
print(" nums =",nums)
print(" start =",start)
print(" curr =",curr)
to the beginning of the backtrack function will show you how it's working through the data. First run it with a two element list, then a three element list, etcetera.
 

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