Finding all subsets of a list of positive integers using backtracking

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Discussion Overview

The discussion revolves around understanding a Python implementation of backtracking to find all subsets of a list of positive integers. Participants seek clarification on how the provided code functions, particularly in the context of backtracking as a technique.

Discussion Character

  • Technical explanation
  • Exploratory

Main Points Raised

  • One participant shares a Python code snippet intended to find all subsets of a list, illustrating the output for a specific example.
  • Another participant provides a similar code snippet but corrects a mistake in the original code regarding how elements are added to the current subset.
  • Several participants express a lack of familiarity with backtracking and request explanations of the code's functionality.
  • Suggestions are made to add print statements to the code to help visualize the execution flow and understand how backtracking operates.
  • A participant references an external resource for further insight into the concept of power sets in Python.

Areas of Agreement / Disagreement

Participants generally agree on the need for clarification regarding backtracking and the code's operation, but there is no consensus on a definitive explanation or understanding of the technique itself.

Contextual Notes

Some participants mention specific strategies for understanding the code, such as working through it line by line or using debugging tools, but these methods are not universally accepted as the only way to grasp the concept.

Andrew1235
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The following Python 3 code is provided as the solution to this problem (https://leetcode.com/problems/subsets/solution/) that asks to find all subsets of a list of integers. For example, for the list below the output is [[], [1], [1, 2], [1, 2, 3], [1, 3], [2], [2, 3], [3]].

I am not familiar with backtracking. Can someone explain how the code works?

alist = [1,2,3]

ans = []

def backtrack(nums, start, curr):

ans.append(curr)

for i in range(start, len(nums)):

backtrack(nums, i+1, curr + [nums])

def subsets(nums):
backtrack(nums, 0, [])
return ans

print(subsets(alist))
 
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Andrew1235 said:
The following Python 3 code is provided as the solution to this problem (https://leetcode.com/problems/subsets/solution/) that asks to find all subsets of a list of integers. For example, for the list below the output is [[], [1], [1, 2], [1, 2, 3], [1, 3], [2], [2, 3], [3]].

I am not familiar with backtracking. Can someone explain how the code works?

Python:
alist = [1,2,3]

ans = []

def backtrack(nums, start, curr):
 
    ans.append(curr) 
    
    for i in range(start, len(nums)):
 
        backtrack(nums, i+1, curr + [nums[i]])

def subsets(nums):     
    backtrack(nums, 0, [])
    return ans
   
print(subsets(alist))
You need to put
Python:
[/color] before your code and
[/color] afterwards if you want it to be readable.

Python:
alist = [1,2,3]
ans = []

def backtrack(nums, start, curr): 
    ans.append(curr)     
    for i in range(start, len(nums)): 
        backtrack(nums, i+1, curr + [nums[i]])

def subsets(nums):     
    backtrack(nums, 0, [])
    return ans
   
print(subsets(alist))
 
Last edited by a moderator:
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Andrew1235 said:
I am not familiar with backtracking. Can someone explain how the code works?
The best (only?) way to understand it is to work through it line by line. You can do this on paper, or by inserting print statements in the code, or by using the 'watch' facitilty of an IDE and stepping through the code.
 
What pbuk said. At the very least, adding
Python:
print("backtrack called with)
print(" nums =",nums)
print(" start =",start)
print(" curr =",curr)
to the beginning of the backtrack function will show you how it's working through the data. First run it with a two element list, then a three element list, etcetera.
 

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