Finding an expression for charge (Q) given an I-V equation

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The discussion focuses on deriving an expression for charge (Q) in an ideal semiconductor diode using the I-V equation I = I_s(e^(V/V_th) - 1). The applied voltage is defined as V = Bt for t ≥ 0, leading to the integral Q(t) = ∫_0^t (I_s e^(B*t/V_th) - I_s) dt. Participants are evaluating whether the integral setup is correct and if the resulting expression accurately reflects the charge passed through the diode. Additionally, the discussion includes plotting I(t), Q(t), power p(t), and total energy w(t) using MATLAB for the specified parameters. The goal is to find the time τ when a total of 1 C of charge has passed through the diode and to determine the corresponding values of power and energy at that time.
VinnyCee
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An ideal semiconductor diode is a nonlinear element that obeys the following I-V equation:

I\,=\,I_s\,\left(\,e^{\frac{V}{V_{th}}}\,-\,1\right)

where I_s is a constant (saturation current) and V_{th} is a constant (thermal voltage, V_{th}\,=\,\frac{k_B\,T}{q}).

Assuming the applied voltage is given by

\begin{displaymath}<br /> V\,=\,\left\{ \begin{array}{ll}<br /> 0 &amp; for\,t\,&lt;\,0 \\<br /> Bt &amp; for\,t\,\geq\,0 \\<br /> \end{array} \right.<br /> \end{displaymath}

where B is a known constant.

Find an analytic expression for the charge Q(t) that has passed through the diode over the period from 0 to t. Also find the analytic expressions for the power dissipated by the diode p(t) and for the total energy dissipated by the diode w(t) over the period from 0 to t.

Now assuming I_s\,=\,1\,\times\,10^{-14},\,V_{th}\,=\,25.85\,mV and B\,=\,90\,\frac{mV}{s} use MATLAB to plot I(t), Q(t), p(t), and w(t). Do your plots for t = 0 to 10s.

Find the time \tau at which a total of 1 C of charge has passed through the diode (Q(\tau)\,=\,1\,C) and find the values of p(\tau) and w(\tau).


MY WORK SO FAR:

Q\,=\,\int_0^t\,i\,dt\,=\,\int_0^t\,\left(I_s\,e^{\frac{V}{V_{th}}}\,-\,I_s\right)\,dt

Q(t)\,=\,\left[I_s\,e^{\frac{V}{V_{th}}}\,t\,-\,I_s\,t\right]_0^t\,=\,\left(I_s\,e^{\frac{V}{V_{th}}}\,-\,I_s\right)\,t

Do I have the first part (equation for Q) of the question right?
 
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Mabye the integral is wrong? Is this better?:

Q\,(t)\,=\,\int_0^t\,\left(I_s\,e^{\frac{B\,t}{V_{th}}}\,-\,I_s\right)\,dt

Q\,(t)\,=\,\left[I_s\,e^{\frac{B\,t}{V_{th}}}\,t\,-\,I_s\,t\right]_0^t\,=\,\left(I_s\,e^{\frac{B\,t}{V_{th}}}\,-\,I_s\right)\,t
 
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