ISU20CpreE
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Hi there i am trying to make this equation look exact.
(Cos(2y)-Sin (x)) dx-2 Tan (x) Sin (2y) dy = 0
What I've done so far is take the partial with respect to x and y.
So, my
M_{y} is equal to -2 Sin (2y)-0 and,
my N_{x} is equal to -2(Sec^{2}(x)) Sin (2y)
Which makes it not exact. So, then I tried using
\frac{M_{y}-N_{x}}{-N} and,
here is where I have tried so many times to find out a way to find an Integration Factor (I.F.)
Any suggestions will help, thanks for your time.
(Cos(2y)-Sin (x)) dx-2 Tan (x) Sin (2y) dy = 0
What I've done so far is take the partial with respect to x and y.
So, my
M_{y} is equal to -2 Sin (2y)-0 and,
my N_{x} is equal to -2(Sec^{2}(x)) Sin (2y)
Which makes it not exact. So, then I tried using
\frac{M_{y}-N_{x}}{-N} and,
here is where I have tried so many times to find out a way to find an Integration Factor (I.F.)
Any suggestions will help, thanks for your time.