Finding Area Moment of Inertia for Axis 33 to X-Axis

[rock.freak667]

Homework Statement

I have to find the area moment of inertia about an axis 33 to the x-axis
http://img227.imageshack.us/img227/2392/shape.jpg

Homework Equations

$$I_\phi=\frac{1}{2}(I_{xx}+I_{yy})+\frac{1}{2}(I{xx}-I_{yy})cos2\phi - I_{xy}sin2\phi$$

The Attempt at a Solution

I found I_xx, but since it is symmetrical, I_xx=I_yy, and since it is symmetrical about the x and y axes, I_xy=0

So the I about any axis is just the 1/2(I_xx+I_yy) = I_xx.

Is my thinking correct, or am I mistaking it?

 

[nickjer]

Looks ok to me.