Teptip
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Thanks, solved!
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Teptip said:Here is the circuit in question: http://imgur.com/glr2C4f
Homework Statement
Find the charge on the 4 µF capacitor if
R1 = 11 Ω and R2 = 4 Ω .
Answer in units of µC
Homework Equations
V = IR
C = Q/V
The Attempt at a Solution
We've never had to deal with capacitors in parallel with resistors before so I'm not sure how this works.
Do I assume the total resistance of the circuit is in series and thus = 16Ω ?
Teptip said:What voltage do I use for the C=Q/V equation?
Teptip said:Okay so I can calculate current I=V/R = 19/16 = 1.1875 A
No, what do you mean of Vtotal? And you do not need it.Teptip said:V total = (V of Capacitor) + (V of 11Ω Resistor)
You know the voltage across the 11 Ω resistor. Look at the figure. Where are the plates of the capacitor connected to?Teptip said:V of 11Ω Resistor = IR = (1.1875)(11) = 13.0625
Teptip said:Is the voltage I want then just the voltage across the 4Ω resistor?
Teptip said:Ah is it the same current as throughout, since the capacitor is quickly charged?
(I = 1.1875 A so V = (1.1875)(4) and then this voltage is the same that would go through the capacitor?)