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tod88
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Finding Coefficient of Friction [solved]
A girl is ice skating at 10 m/s. She stops skating and glides to a stop in 100m. Find the coefficient of friction of the ice.
uk = Fk / Fn
F=ma
I found the acceleration to be -1/2 m/s^2 since
Vf^2 = Vi^2 + 2a * displacement
so
-100 / 200 = a.
Since it didn't give me her weight I don't know how to find gravitational force on her. If the surface were frictionless her acceleration would be zero.
Since her acceleration isn't zero and it takes her 20 seconds to come to a stop, I know that there must be a uk and that it also must be very small. Without her weight, however, I'm lost. Can someone point me in the right direction?
Homework Statement
A girl is ice skating at 10 m/s. She stops skating and glides to a stop in 100m. Find the coefficient of friction of the ice.
Homework Equations
uk = Fk / Fn
F=ma
The Attempt at a Solution
I found the acceleration to be -1/2 m/s^2 since
Vf^2 = Vi^2 + 2a * displacement
so
-100 / 200 = a.
Since it didn't give me her weight I don't know how to find gravitational force on her. If the surface were frictionless her acceleration would be zero.
Since her acceleration isn't zero and it takes her 20 seconds to come to a stop, I know that there must be a uk and that it also must be very small. Without her weight, however, I'm lost. Can someone point me in the right direction?
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