How Do You Calculate the Constants A and C for a Rocket's Trajectory Equation?

AI Thread Summary
To calculate the constants A and C for a rocket's trajectory, the position coordinates are defined as x(t)=A+Bt^2 and y(t)=C+Dt^3, with known acceleration values. After deriving the position equations, it was determined that D equals 0.500 m/s^3 and B equals 2.00 m/s^2. The initial height of the rocket, given as 50.0 m, indicates that C should be set to 50.0 m. A represents the initial horizontal position, which needs to be determined based on the context of the problem. The discussion emphasizes the importance of understanding initial conditions to solve for A and C accurately.
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A rocket is fired at an angle from the top of a tower of height 50.0m. Because of the designs of its engines, its position coordinates are of the form x(t)=A+Bt^2 and y(t)=C+Dt^3, where A, B, C, and D are constants. The acceleration of the rocket after 1.00s after firing is a= (4.00i+3.00j)m/s^2. Find the constants A, B, C, and D including their SI units.

I took the derivative of the position vectors twice to get the acceleration vector and plugged in 1.00s into t to find D=0.500m/s^3 and B=2.00m/s^2. I am stuck on where to go after that to get A and C.
 
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azn4lyf89 said:
A rocket is fired at an angle from the top of a tower of height 50.0m. Because of the designs of its engines, its position coordinates are of the form x(t)=A+Bt^2 and y(t)=C+Dt^3, where A, B, C, and D are constants. The acceleration of the rocket after 1.00s after firing is a= (4.00i+3.00j)m/s^2. Find the constants A, B, C, and D including their SI units.

I took the derivative of the position vectors twice to get the acceleration vector and plugged in 1.00s into t to find D=0.500m/s^3 and B=2.00m/s^2. I am stuck on where to go after that to get A and C.

What is C. Wasn't it given to you? What is A then? Remember the equation describes position. Where was its initial position?
 
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