Is the Current Calculation in the Circuit Incorrect?

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The discussion centers on the calculation of current (IL) in a circuit, specifically questioning the formula IL = Vs/Req, where Vs is 458.3kV and Req is the sum of two resistors (240 ohms). One participant argues that the book's calculation is incorrect for omitting the 20-ohm resistor, while others assert that the book's answer is valid as it focuses on the current through the load resistor (Rload). The current remains the same through both resistors, but the voltage drop is measured against the load resistance, which helps determine the source voltage. Ultimately, the consensus is that the book's approach correctly calculates the current and voltage drop in the circuit.
Miike012
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I think the book is wrong.

Why is the current (which they denote IL) equal to Vs/(Req)

Where Vs = 458.3kV and Req is the equivalent resistance of the circuit equal to the sum of the two resistors in series ( Req = 220 + 20 = 240).

In there equation they left out the the resistor of 20 ohmes
 

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No, the book answer is correct. They are finding the current in Rload by knowing Iload = Vload/Rload.
Now that you know the current, you can find the voltage drop across the 20 okm line resistance. Then you can find the source voltage.
 
barryj said:
No, the book answer is correct. They are finding the current in Rload by knowing Iload = Vload/Rload.
Now that you know the current, you can find the voltage drop across the 20 okm line resistance. Then you can find the source voltage.

Why is the current different through each resistor?
 
Miike012 said:
Why is the current different through each resistor?

It's not. That's what barryj is saying. They are the same. But the voltage drop is only measured against the load resistance. You can use that to find the source voltage.
 

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