PrincessPerry said:So would this be right?
I0 = I1 + I2
I2 = 6 - 2
I2 = 3 A
gneill said:It looks fine. What else can you find now that you have I2?
gneill said:What's left to solve for? Do you have enough information now to calculate it?
PrincessPerry said:I need to find the value for V0. And to do that, I need to find R0.
gneill said:R0? What's that? I see an R2 and what is no doubt the R1 that you found a value for above. Maybe you're thinking of Rp, the resistance of R1 and R2 in parallel?
As for V0, isn't that the voltage to be assigned to the voltage source? If so, do you already have a value for the potential across the source?
PrincessPerry said:So would this be right?
I0 = I1 + I2
I2 = 6 - 2
I2 = 3 A
Janus said:Since when does 6-2=3?
gneill said:Isn't the battery in parallel with the resistances? You already used the voltage property of parallel branches when you determined the voltage across R1...
And isn't the Rp the net resistance that you're looking for?
gneill said:Isn't the battery in parallel with the resistances? You already used the voltage property of parallel branches when you determined the voltage across R1...
And isn't the Rp the net resistance that you're looking for?