Finding delta in terms of epsilon-delta definition

Bolz
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Homework Statement



If f(x) = 3x+1 en assume δ > 0. Assume ε>0.
Give a δ > 0 with the following property :

|x-1|< δ => |f(x) - f(1)| < ε

Homework Equations





The Attempt at a Solution




|f(x) - f(1)| < ε
<=> |3x+1-(3*1+1)| < ε
<=> |3x-3| < ε
<=> |x-1| < ε/3


|x-1| < δ
|x-1| < ε/3


=> δ=ε/3>0


What am I doing wrong?

Thanks in advance!
 
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Bolz said:

Homework Statement



If f(x) = 3x+1 en assume δ > 0. Assume ε>0.
Give a δ > 0 with the following property :

|x-1|< δ => |f(x) - f(1)| < ε

Homework Equations





The Attempt at a Solution




|f(x) - f(1)| < ε
<=> |3x+1-(3*1+1)| < ε
<=> |3x-3| < ε
<=> |x-1| < ε/3


|x-1| < δ
|x-1| < ε/3


=> δ=ε/3>0


What am I doing wrong?

Nothing. Your solution is correct.
 
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pasmith said:
Nothing. Your solution is correct.

Oh ok. I'm learning this on my own so I assumed it had to be wrong. Self confidence is important in math too apparently..
Anyway, thanks for checking it! :)
 
Then it would have been better to ask "Is this correct" rather than "What am I doing wrong"! You are not going to do very well assuming that you cannot do the work.
 
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HallsofIvy said:
Then it would have been better to ask "Is this correct" rather than "What am I doing wrong"! You are not going to do very well assuming that you cannot do the work.


Sorry, you're right. I'm just struggling with a lot in life and I think my lack of self confidence leaked into doing math. Sorry again.
 
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