Finding Derivatives of -2z*e^-(z^2)

[T.Engineer]

find the 1st and 2nd derivative of the following equation

-2z*e^-(z^2)
step by step.
Thanks alot!

 

[radou]

Any ideas on this one? if this is a function of z, and you're differentiating with respect to z, does the product rule sound familiar?

 

[T.Engineer]

Any ideas on this one? if this is a function of z, and you're differentiating with respect to z, does the product rule sound familiar?

Ok, I get it
it is -2Z (-2z)e^-(z^2) - [e^-(z^2)*(-2)]
and then:
4z^2 * e^-(z^2) + 2e^-(z^2)
Thanks alot!

 

[CompuChip]

it is -2Z (-2z)e^-(z^2) ---[/color] [e^-(z^2)*(-2)]

Yep, that's the way to go.
But are you sure about that minus sign?
Can you quote the product rule?

 

[T.Engineer]

Yep, that's the way to go.
But are you sure about that minus sign?
Can you quote the product rule?

Oh, I am so sorry it is
-2Z (-2z)e^-(z^2)+ [e^-(z^2)*(-2)]
So, we will have
4z^2*e^-(z^2)-2e^-(z^2)

 

[rhymes116]

that looks right. Remember, (first) *(derivative of the second) + (second) * (derivative of first). Of course you can change the order, same answer.

 

[T.Engineer]

thanks a lot for all!