Finding Eccentricity of Orbit Given Masses, Positions, and Velocities

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SUMMARY

The discussion focuses on calculating the eccentricity of an orbit using the reduced mass approach in the xy plane. The formula used is ε = √(1 + (2 E L²) / (μ k²)), where E represents energy, L is angular momentum, μ is the reduced mass, and k is the gravitational constant multiplied by the masses of the two particles. Key calculations involve determining the velocity and position of the reduced mass "particle" as the differences between the respective particles' velocities and positions. The participant seeks confirmation on the correctness of their method and alternative approaches.

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  • Understanding of celestial mechanics and orbital dynamics
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  • Knowledge of angular momentum and energy equations in physics
  • Proficiency in vector operations, particularly cross products
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Homework Statement


Find the eccentricity of an orbit given the masses, cartesian position components, and cartesian velocity components for particles 1 and 2. The case is reduced to the xy plane.

Homework Equations


I am attempting this problem using reduced mass from the center of mass frame.
ε = [itex]\sqrt{1 + \frac{2 E L^2}{\mu k^2}}[/itex]
where
E = energy
L = [itex]\mu r^2 \dot{\theta}[/itex]
μ = [itex]\frac{m1m2}{m1+m2}[/itex]
k = Gm1m2
r = distance between the two particles

The Attempt at a Solution


I have two general questions. 1) Is the method below correct? If no, I would appreciate guidance to correct the method. 2) If there a better method?

If I knew the velocity, energy, and angular momentum of the reduced mass "particle", I could input the information into the relevant equation.

Is the velocity v of the reduced mass "particle" the difference between the velocities of particles 1 and 2? Similarly, is the position r of the "particle the difference between the positions of particles 1 and 2?

Given the velocity, would the energy of the "particle" be [itex]E = \frac{1}{2}μv^2- \frac{Gm1m2}{r}[/itex] ?

Would the angular momentum L of the "particle" be μ* r x v? Where I would take the cross product of the "particle's" position and velocity components then find the square L^2?

Thank you.
 
Physics news on Phys.org
Hello!
One of my assignments for a discipline named planetary systems was to write a program and a paper about the orbit of Eris.
One of the tasks was to find the orbit's characteristics with only one arbitrary point of position and velocity.

Take a look ;)

My best regards, Iris.
 

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