Finding Ek with force, mass, and time.

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A 10kg box is pushed on a frictionless surface with a 10N force, resulting in an acceleration of 1 m/s². After 10 seconds, the final velocity is calculated to be 10 m/s. Using the kinetic energy formula, the final kinetic energy is determined to be 500J. The calculation is confirmed by considering the work done by the force over the distance traveled. The conclusion is that the calculated kinetic energy of 500J is indeed correct.
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Homework Statement



A 10kg box at rest is being pushed on a frictionless surface by a force of 10N. The force is in the same direction as the motion of the box. 10 seconds later, how much kinetic energy will this box have?

Homework Equations



1. F=ma
2. Vf=Vi+at
3. Ek=0.5mv2

The Attempt at a Solution



I used formula 1 along with the F and mass to find the acceleration to be 1 m/s2. Then, I plugged that into formula 2, given an initial velocity of 0, acceleration of 1 m/s2, and a time of 10s. This gave me Vf at 10m/s. I used that in formula 3, with mass being 10kg. This gave me a final Ek of 500J.

Is this correct? 500J seems a little high but, I've no clue how else to do this. Thanks in advance.
 
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1J is the energy exerted by a force of 1N thaat moves an object by 1m. The force in this case is 10N and the distance is 50m(0.5at^2=100/2), so 500J seems fine.
 
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