Finding Equivalent Resistance in Resistor Network - Can You Help?

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The discussion revolves around calculating the equivalent resistance between points A and B in a resistor network. The initial assumption that resistors R5 and R6 are in parallel was incorrect due to their connection configuration. It was clarified that R4 and R3 are actually in parallel, resulting in a combined resistance of 2k, which is then in series with R5. This total resistance is subsequently in parallel with R6, leading to the correct equivalent resistance of 4k. The importance of understanding the connections and applying Kirchhoff's Law was emphasized for accurate calculations.
kdinser
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Can someone tell me where I'm going wrong here?
I'm uploading a jpeg of the circuit, I'm supposed to find the equivalent resistance between A and B.

To me, it looks like R5 and R6 are in parallel and forming Rp56. From there I'm assuming that Rp56 would be in parallel with R3 and then that whole top part (R5, R6, and R3) would be in series with R4.

Can someone point out where I'm making my error? I'm coming up with a total resistance of 5k and the answer should be 4k.
 

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kdinser said:
To me, it looks like R5 and R6 are in parallel and forming Rp56. From there I'm assuming that Rp56 would be in parallel with R3
This is incorrect because the chain is more complex due to the different interconnecting wires. What you need to do is to apply Kirchoff's Law. Do you know this procedure ? You basically apply charge conservation and energy conservation on each subchain. So, the first thing to do is to detect each subchain (you have three such chaines in your case).

marlon
 
kdinser said:
To me, it looks like R5 and R6 are in parallel and forming Rp56. From there I'm assuming that Rp56 would be in parallel with R3 and then that whole top part (R5, R6, and R3) would be in series with R4.

To be in parallel, the two resistors have to have the same potentials at BOTH ends, which means both their ends touch each other. Here 5 and 6 only touch at one end. Shorten all the wires and redraw the circuit without wires and see which resistors touch at both ends. I did it and came up with 4k as the answer.
 
I think I have it, at least I'm coming up with the correct answer now.

Going back to the original diagram, R4 and R3 are in parallel giving a resistance of 2k which is in series with R5. This equivalent resistance is then in parallel with R6.

Sound right? Thanks for the help guys.

Oh, and thanks for not just spewing out the answer, it makes a lot more sense now.

Keith
 
kdinser said:
Going back to the original diagram, R4 and R3 are in parallel giving a resistance of 2k which is in series with R5. This equivalent resistance is then in parallel with R6.

Sound right?

That's the way I got it.
 

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