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## Homework Statement

Oil flowing through a pipe, measured to be 135kPa 15m from the end and 88kPa discharging from the end. The diameter of the pipe is 1.5cm, the density of the oil is 876kg/m^3, and the dynamic viscosity is 0.24kg/m*s.

Find flow rate for:

a) horizontal

b) inclined 8 degrees

c) declined 8 degrees

## Homework Equations

[tex] Re=V*D*\rho / \mu [/tex]

[tex] \Delta P = h_L * \rho *g [/tex]

[tex] h_L = f*(L/D)*(V^2)/(2*g) [/tex]

[tex] f=64/Re [/tex] (laminar flow only)

where:

Re = Reynolds Number

rho = density[tex] f=64/Re [/tex]

mu = dynamic viscosity

delta P = pressure loss

h_L = head loss

L = length

D = diameter

f = Darcy friction coefficient

## The Attempt at a Solution

I solved for Re in terms of V, and for V in terms of f, and then I guessed f=0.0150 for a starting point. I got an Re of 13.8, indicating laminar flow, so I used [tex] f=64/Re [/tex] and iterated. However, my answer finally converged on f=12734.79 which doesn't look at all right. Am I doing something wrong?